This is likely to change as const generics functionality is improved, for example `feature(associated_const_equality)` and `feature(min_generic_const_args)` both require handling const aliases similarly to types (without an anonymous constant wrapping all const args).
## What is Normalization
### Structural vs Deep normalization
There are two forms of normalization, structural (sometimes called *shallow*) and deep. Structural normalization should be thought of as only normalizing the "outermost" part of a type. On the other hand deep normalization will normalize *all* aliases in a type.
In practice structural normalization can result in more than just the outer layer of the type being normalized, but this behaviour should not be relied upon. Unnormalizable non-rigid aliases making use of bound variables (`for<'a>`) cannot be normalized by either kind of normalization.
As an example: conceptually, structurally normalizing the type `Vec<<u8 as Identity>::Assoc>` would be a no-op, whereas deeply normalizing would give `Vec<u8>`. In practice even structural normalization would give `Vec<u8>`, though, again, this should not be relied upon.
Changing the alias to use bound variables will result in different behaviour; `Vec<for<'a> fn(<&'a u8 as Identity>::Assoc)>` would result in no change when structurally normalized, but would result in `Vec<for<'a> fn(&'a u8)>` when deeply normalized.
### Core normalization logic
Structurally normalizing aliases is a little bit more nuanced than replacing the alias with whatever it is defined as being equal to in its definition; the result of normalizing an alias should either be a rigid type or an inference variable (which will later be inferred to a rigid type). To accomplish this we do two things:
First, when normalizing an ambiguous alias it is normalized to an inference variable instead of leaving it as-is, this has two main effects:
- Even though an inference variable is not a rigid type, it will always wind up inferred *to* a rigid type so we ensure that the result of normalization will not need to be normalized again
- Inference variables are used in all cases where a type is non-rigid, allowing the rest of the compiler to not have to deal with *both* ambiguous aliases *and* inference variables
Secondly, instead of having normalization directly return the type specified in the definition of the alias, we normalize the type first before returning it[^1]. We do this so that normalization is idempotent/callers do not need to run it in a loop.
```rust
#![feature(lazy_type_alias)]
type Foo<T: Iterator> = Bar<T>;
type Bar<T: Iterator> = <T as Iterator>::Item;
fn foo() {
let a_: Foo<_>;
}
```
In this example:
- Normalizing `Foo<?x>` would result in `Bar<?x>`, except we want to normalize aliases in the type `Foo` is defined as equal to
- Normalizing `Bar<?x>` would result in `<?x as Iterator>::Item`, except, again, we want to normalize aliases in the type `Bar` is defined as equal to
- Normalizing `<?x as Iterator>::Item` results in some new inference variable `?y`, as `<?x as Iterator>::Item` is an ambiguous alias
- The final result is that normalizing `Foo<?x>` results in `?y`
## How to normalize
When interfacing with the type system it will often be the case that it's necessary to request a type be normalized. There are a number of different entry points to the underlying normalization logic and each entry point should only be used in specific parts of the compiler.
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An additional complication is that the compiler is currently undergoing a transition from the old trait solver to the new trait solver.
As part of this transition our approach to normalization in the compiler has changed somewhat significantly, resulting in some normalization entry points being "old solver only" slated for removal in the long-term once the new solver has stabilized.
The transition can be tracked via the [WG-trait-system-refactor](https://github.com/rust-lang/rust/labels/WG-trait-system-refactor) label in Github.